diff --git a/content/optimal-privacy.md b/content/optimal-privacy.md
index 70f12b99..acdc4552 100644
--- a/content/optimal-privacy.md
+++ b/content/optimal-privacy.md
@@ -1,5 +1,5 @@
 +++
-date = "2018-12-07T21:08:39-08:00"
+date = "2018-12-07T00:00:00-08:00"
 title = "Privacy is Consent (alt: On Optimal Privacy vs. System Efficiency)"
 +++
 
@@ -47,11 +47,11 @@ $$f(x,y) = \begin{pmatrix}0 & 1 & 0 & 1 & 0 & 1 & \dots \\\ 1 & 0 & 1 & 0 & 1 &
 
 Such a function can be partitioned based on a single bit of information e.g. whether $y$ is divisible by 2:
 
-$$f(x,y) = \begin{pmatrix}1 & 1 & 1 & \dots\\\ 0 & 0 & 0 & \dots\\\ 1 & 1 & 1 & \dots \\\ 0 & 0 & 0 & \dots \\\ \vdots & \vdots & \vdots  & \vdots \ddots  \end{pmatrix}$$
+$$f(x,y) = \begin{pmatrix}1 & 1 & 1 & \dots\\\ 0 & 0 & 0 & \dots\\\ 1 & 1 & 1 & \dots \\\ 0 & 0 & 0 & \dots \\\ \vdots & \vdots & \vdots  & \vdots & \ddots  \end{pmatrix}$$
 
 or not:
 
-$$f(x,y) = \begin{pmatrix}0 & 0 & 0 & \dots \\\ 1 & 1 & 1 & \dots\\\ 0 & 0 & 0 & \dots\\\ 1 & 1 & 1 & \dots \\\ \vdots & \vdots & \vdots  & \vdots \ddots  \end{pmatrix}$$
+$$f(x,y) = \begin{pmatrix}0 & 0 & 0 & \dots \\\ 1 & 1 & 1 & \dots\\\ 0 & 0 & 0 & \dots\\\ 1 & 1 & 1 & \dots \\\ \vdots & \vdots & \vdots  & \vdots & \ddots  \end{pmatrix}$$
 
 We can partition each matrix again, based on whether $x$ is divisible by 2 or not. Regardless of which of the above partitioned matrices we start with, the resulting matrices are the same:
 
diff --git a/content/random-notes b/content/random-notes
new file mode 100644
index 00000000..fa352930
--- /dev/null
+++ b/content/random-notes
@@ -0,0 +1,36 @@
+e   0 1 2 3
+   -------
+0| 0 1 0 1
+1| 1 0 1 0
+2| 0 1 0 1
+3| 1 0 1 0 
+
+f(2,1) = 1 (y is either 1 or 3 | x is either 0 or 2)
+
+p1 sends 0
+
+   0 1 2 3
+0| 0 1 0 1
+2| 0 1 0 1
+
+p2 sends 1
+
+  1 3
+  ---
+0| 1 1 
+2| 1 1
+
+Why AND Fails:
+
+   0 1 2 3
+   --------
+0| 0 0 0 0
+1| 0 1 0 1
+2| 0 0 1 1   
+3| 0 1 1 1
+
+f(1,2) = 1
+
+p1 sends....there is no way to send information without revealling out input...the matrix is not partitionable.
+
+