Make memwipe() do nothing when passed a NULL pointer or zero size
Check size argument to memwipe() for underflow.
Closes bug #18089. Reported by "gk", patch by "teor".
Bugfix on 0.2.3.25 and 0.2.4.6-alpha (#7352),
commit 49dd5ef3
on 7 Nov 2012.
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@ -0,0 +1,6 @@
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o Minor fixes (security):
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- Make memwipe() do nothing when passed a NULL pointer
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or zero size. Check size argument to memwipe() for underflow.
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Closes bug #18089. Reported by "gk", patch by "teor".
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Bugfix on 0.2.3.25 and 0.2.4.6-alpha (#7352),
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commit 49dd5ef3 on 7 Nov 2012.
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@ -2972,6 +2972,7 @@ secret_to_key(char *key_out, size_t key_out_len, const char *secret,
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/**
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* Destroy the <b>sz</b> bytes of data stored at <b>mem</b>, setting them to
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* the value <b>byte</b>.
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* If <b>mem</b> is NULL or <b>sz</b> is zero, nothing happens.
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*
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* This function is preferable to memset, since many compilers will happily
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* optimize out memset() when they can convince themselves that the data being
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@ -2989,6 +2990,13 @@ secret_to_key(char *key_out, size_t key_out_len, const char *secret,
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void
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memwipe(void *mem, uint8_t byte, size_t sz)
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{
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if (mem == NULL || sz == 0) {
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return;
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}
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/* Data this large is likely to be an underflow. */
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tor_assert(sz < SIZE_T_CEILING);
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/* Because whole-program-optimization exists, we may not be able to just
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* have this function call "memset". A smart compiler could inline it, then
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* eliminate dead memsets, and declare itself to be clever. */
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